Because I actually want to use the 20% too, but if it will demage my battery, I would prefere to cost it. It’s additionally potential that something inside the battery has gone mistaken. Having charged my LiOn battery, and on the multimeter it exhibits up as 4.2V, my digicam nonetheless shows “battery empty” once I swap it on, and would then switch off mechanically. Ultimately, if that’s your solely charger, then you don’t have a choice.

I’m working on a Li-Ion battery pack 6-cell, 10.8V 5600mAh, coming from my macbook. additional four.2 Volts, or scale back the cost voltage to 118.9 Volts, and so on and so forth. I am engaged on an EV Motorbike project, and at the stage the place we now have chosen the batteries, and try to make out personal charging and Very basic BMS system. There might be a drop in current , nonetheless at 1.3ohms I suppose it will be small. If I keep in mind right (DC theory was a very long time ago!) it will be proportional to the dimensions of the resistance.

I assume that once the sunshine turns inexperienced, it quits sending out a charge. So leaving it on the charger won’t accomplish anything if that’s true, nor will it damage something.

I guess it could depend on your charger, and what makes it resolve to show green. But after I wait a while and let things settle, I’ll have room again for a little more.

Most important is the longest potential life with respect to remaining capacity. It needs to be out there for at least 5 years with out service, higher 10 or extra.

I’m making an attempt to include a built-in charger utilizing a purpose IC - MCP73831 or MCP73837. I’m constructing a small battery operated radio powered by a mAh . But remember that the quantity of cost stored in a cell cannot be measured, so your telephone is simply guestimating those percentages. 4.2V is often considered 100% full, which means that you simply don’t want to go greater than that. For it to be four.2V and nonetheless present solely 67% charged means you cellphone is making unhealthy guesses.